1:14 AM The Hamilton-Jacobi Equation | |
The Hamilton-Jacobi EquationMichael Fowler Back to Configuration SpaceWe've established that the action, regarded as a function of its coordinate endpoints and time, satisfies and at the same time This is the Hamilton-Jacobi equation. Notice that we're now back in configuration space! For example, the Hamilton-Jacobi equation for the simple harmonic oscillator in one dimension is (Notice that this has some resemblance to the Schrödinger equation for the same system.) If the Hamiltonian has no explicit time dependence (This is analogous to the time independent Schrödinger equation for energy eigenstates.) The Hamilton-Jacobi equation is therefore a third complete description of the dynamics, equivalent to Lagrange's equations and to Hamilton's equations. Since the The Central Role of These Constants of IntegrationTo describe the time development of a dynamical system in the simplest way possible, it is desirable to find parameters that are constant or change in a simple way. For example, motion in a spherically symmetric potential is described in terms of (constant) angular momentum components. Now, these constant How do we find the generating function for this transformation? A clue comes from one we've already discussed: that corresponding to development in time, going from the initial set of variables to the final set, or back. That transformation was generated by the action itself, expressed in terms of the two sets of positions. That is, we allowed both ends of the action integral path to vary, and wrote the action as a function of the final In the present section, the final endpoint positions are denoted simply by Compare this expression for the action with the formal expression we just derived from the Hamilton Jacobi equation, These two expressions for Now, just as we showed the action generated the transformation (either way) between the initial set of coordinates and momenta and the final set, it will also generate a canonical transformation from the final set of coordinates and momenta to another canonical set, having the Taking then the action (neglecting the constant Recall
so here
and This defines the new "coordinates" To find the new Hamiltonian But where The first equation in this section was so the new Hamiltonian We have made a canonical transformation that has led to a zero Hamiltonian! What does that mean? It means that the neither the new momenta nor the new coordinates vary in time:
(The fact that all momenta and coordinates are fixed in this representation does not mean that the system doesn't move -- as will become evident in the following simple example, the original coordinates are functions of these new (nonvarying!) variables and time.) The A Simple Example of the Hamilton-Jacobi Equation: Motion Under GravityThe Hamiltonian for motion under gravity in a vertical plane is so the Hamilton-Jacobi equation is First, this Hamiltonian has no explicit time dependence (gravity isn't changing!), so from A Simple Separation of VariablesSince the potential energy term depends only on Putting this form into the equation, the resulting first term depends only on the variable Labeling the constants So these Solving, (We could add in constants of integration, but adding constants to the action changes nothing.) So now we have This is our generating function (equivalent to These equations solve the problem. Rearranging, the trajectory is The four "constants of motion" Separation of Variables for a Central Potential; Cyclic VariablesLandau presents in some details the separation of variables method for a How do we make any progress with these formidable differential equations? One possibility is that some coordinates are cyclic, meaning that The Hamiltonian for a central potential is: The Hamilton-Jacobi equation is therefore The first thing to note is that Then we have: Now we seek a solution of the form Substituting in the equation, notice that the expression in square brackets will become independent of and then These first-order equations can then be solved, at least numerically (and of course exactly for some cases). Physically, Note: recall that in quantum mechanics, for example in solving the Schrödinger equation for the hydrogen atom, the separation of variables was achieved by writing the wave function as a product of functions belonging to the different variables. Here we use a sum -- remember that the action corresponds closely to the phase of a quantum mechanical system, so a sum of actions is analogous to a product of wave functions. | |
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